A) \[{{10}^{-17}}{{\mu }_{0}}\]
B) \[{{10}^{-11}}{{\mu }_{0}}\]
C) \[{{10}^{-7}}{{\mu }_{0}}\]
D) \[{{10}^{-3}}{{\mu }_{0}}\]
Correct Answer: A
Solution :
Charge on the particle \[=100\text{ }C\] \[=100\times 1.6\times {{10}^{-19}}=1.6\times {{10}^{-17}}C\] Radius of circular path \[r=0.8\text{ }m\] Time period \[t=1\]rotation/sec The current in the particle is \[i=\frac{\text{charge}}{\text{time}}=\frac{1.6\times {{10}^{-17}}}{1}=1.6\times {{10}^{-17}}\,\text{amp}\] The centre of the coil is given by \[B=\frac{{{\mu }_{0}}i}{r}=\frac{{{\mu }_{0}}\times 1.6\times {{10}^{-17}}}{2\times 0.8}={{10}^{-17}}{{\mu }_{.0}}\]
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