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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    The energy of hydrogen atom in its ground state is \[-13.6\text{ }eV.\] The energy of the level corresponding to the quantum number\[n\]is equal 5 is:

    A) \[-5.40\,eV\]                     

    B) \[~-2.72\,eV\]

    C) \[~-\text{ }0.85\text{ }eV\]        

    D) \[~-\text{ }0.54\text{ }eV\]

    Correct Answer: D

    Solution :

    Energy in ground state \[{{E}_{1}}=-13.6\,eV\] Energy level\[n=5\]            (given) The energy of hydrogen atom at level 5, is \[{{E}_{5}}=-\frac{13.6}{{{n}^{2}}}=\frac{13.6}{{{5}^{2}}}=\frac{13.6}{25}\] \[=0.54\,eV\]


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