A) 3.3
B) 4.3
C) 4.0
D) 4.5
Correct Answer: A
Solution :
Aqueous solution of pH 6 means, \[[{{H}^{+}}]={{10}^{-6}}\] Aq. solution of pH 3 means, \[[{{H}^{+}}]={{10}^{-3}}\] Aq. solutions of both pH are mixed in equal volume, hence \[[{{H}^{+}}]=\frac{{{10}^{-6}}+{{10}^{-3}}}{2}\] \[={{10}^{-6}}\left( \frac{1+{{10}^{3}}}{2} \right)\] or \[={{10}^{-6}}\times \frac{1001}{2}={{10}^{-6}}\times 550\] \[\therefore \] \[pH=-\log [{{H}^{+}}]\] \[=6-\log 550\] \[=6-2.7404\] \[=3.2596\] \[3.3\]
You need to login to perform this action.
You will be redirected in
3 sec
