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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    75% of a first order reaction is completed in 30 minutes. What is the time required for 93.75% of the reaction (in minutes)?

    A)  45                                         

    B)  120

    C)  90                                         

    D)  60

    Correct Answer: D

    Solution :

    \[{{t}_{1/2}}\]is \[\frac{1}{2}{{t}_{0}}.75\] \[\therefore \]\[{{t}_{1/2}}=\frac{1}{2}\times 30=15\,\]minute \[93.75%\]of reaction can be completed in \[4\times {{t}_{1/2}}=4\times 15=60\]minute


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