2. Solved Papers
  3. CET Karnataka Engineering

CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2002

  • question_answer
    20 ml of \[\text{0}\text{.25}\,\text{N}\]strong acid and 30 ml \[\text{0}\text{.2}\,\text{N}\]of strong base are mixed; the resulting solution is:

    A)  \[\text{0}\text{.02 N}\]acidic    

    B) \[0.025\]N basic

    C) \[\text{ }\!\!~\!\!\text{ 0}\text{.02 N}\] basic   

    D) \[\text{ }\!\!~\!\!\text{ 0}\text{.025 N}\]acidic

    Correct Answer: C

    Solution :

    \[{{V}_{1}}=20\,ml,\,{{N}_{1}}=0.25\,N,\,{{V}_{2}}=30\,ml,\]\[{{N}_{2}}=0.2\,N\] \[\because \]\[N=\frac{{{N}_{1}}{{V}_{1}}+{{N}_{2}}{{V}_{2}}}{{{V}_{1}}+{{V}_{2}}}=\frac{20(0.25)+30(0.2)}{20+30}\] \[-\frac{5+6}{50}=\frac{11}{50}=0.2\,N,\]basic


You need to login to perform this action.
You will be redirected in 3 sec spinner