A) \[\text{0}\text{.02 N}\]acidic
B) \[0.025\]N basic
C) \[\text{ }\!\!~\!\!\text{ 0}\text{.02 N}\] basic
D) \[\text{ }\!\!~\!\!\text{ 0}\text{.025 N}\]acidic
Correct Answer: C
Solution :
\[{{V}_{1}}=20\,ml,\,{{N}_{1}}=0.25\,N,\,{{V}_{2}}=30\,ml,\]\[{{N}_{2}}=0.2\,N\] \[\because \]\[N=\frac{{{N}_{1}}{{V}_{1}}+{{N}_{2}}{{V}_{2}}}{{{V}_{1}}+{{V}_{2}}}=\frac{20(0.25)+30(0.2)}{20+30}\] \[-\frac{5+6}{50}=\frac{11}{50}=0.2\,N,\]basicYou need to login to perform this action.
You will be redirected in
3 sec