A) \[Z=12,M=27\]
B) \[Z=13,M=27\]
C) \[Z=12,M=17\]
D) \[Z=13,M=28\]
Correct Answer: B
Solution :
\[{{\,}_{Z}}{{X}^{M}}+{{\,}_{2}}H{{e}^{4}}\xrightarrow{{}}{{\,}_{15}}{{P}^{30}}+{{\,}_{0}}{{n}^{1}}\] Here \[Z=13\]and \[M=17\] Hence \[{{\,}_{13}}{{X}^{17}}+{{\,}_{2}}H{{e}^{4}}\xrightarrow{{}}{{\,}_{15}}{{P}^{30}}+\,{{ & }_{0}}{{n}^{1}}\]You need to login to perform this action.
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