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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2002

  • question_answer
    A body is projected vertically upwards from the surface of a planet of radius R with a velocity equal to half the escape velocity for that planet. The maximum height attained by the body is:

    A)  R/2                                       

    B)  R/3

    C)  R/5                                       

    D)  R/4

    Correct Answer: B

    Solution :

    \[u={{\upsilon }_{e}}/2,\,{{\upsilon }_{e}}=\]escape velocity of body for that planet \[{{h}_{\max }}=\frac{{{u}^{2}}}{2g}R=\] radius of planet \[=\frac{\upsilon _{e}^{2}}{u\times 2g}\] \[g=\]acceleration Due to gravity at that planet .\[=\frac{2Rg}{u\times 2g}{{\upsilon }_{e}}=\sqrt{2\,Rg}\] \[{{h}_{\max }}=R/4\]


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