CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    The maximum of \[4{{\sin }^{2}}x+3{{\cos }^{2}}x\] is :

    A)  4                                            

    B)  3

    C)  7                                            

    D)  5

    Correct Answer: A

    Solution :

    \[4{{\sin }^{2}}x+3{{\cos }^{2}}x\] \[4{{\sin }^{2}}x+3\,(1-{{\sin }^{2}}x)\] \[4{{\sin }^{2}}x+3-3\,\,{{\sin }^{2}}x\] \[{{\sin }^{2}}x+3\] maximum value of \[\sin x\] is 1 at \[x=\pi /2\] So, \[{{(1)}^{2}}+3=4\]  


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