A) \[n\beta \]
B) \[\frac{\beta }{n+1}\]
C) \[\frac{\beta }{n-1}\]
D) \[\frac{\beta }{n}\]
Correct Answer: D
Solution :
Fringe width \[\beta =\frac{2\lambda }{2d}\] (for air) ... (i) When entire arrangement is placed in a liquid of refractive index n, then it becomes \[\beta =\frac{D\lambda }{2d}\] ?. (ii) \[As,\,\,n=\frac{\lambda }{\lambda }\] so, from eq. (i) and (ii) \[\frac{\beta }{\beta }=\frac{D\lambda }{2d}\times \frac{2d}{D\lambda }\Rightarrow \beta =\frac{\beta }{n}\]
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