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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    If elements with principal quantum number \[n>4\]were not allowed in nature, the number of possible elements would have been:

    A)  32                                         

    B)  60

    C)  64                                         

    D)  4

    Correct Answer: B

    Solution :

    For \[n>4\] the possible numbers of elements                 \[=2\,\left[ n_{1}^{2}+n_{2}^{2}+n_{3}^{2}+n_{4}^{2} \right]\]                 \[=2[{{(1)}^{2}}+{{(2)}^{2}}+{{(3)}^{2}}+{{(4)}^{2}}]\]                 \[=2([1+4+9+16]=60\]


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