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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    A hypothetical radioactive nucleus decays according to the following series \[_{72}{{A}^{180}}\xrightarrow{\alpha }{{A}_{1}}\xrightarrow{{{\beta }^{-}}}{{A}_{2}}\xrightarrow{\alpha }{{A}_{3}}\xrightarrow{\gamma }{{A}_{4}}\] If the mass number and atomic number of A are respectively 180 and 72. Then the atomic number and mass number of A will respectively be:

    A)  69, 171                                

    B)  70, 172

    C)  68, 172                                

    D)  69, 172

    Correct Answer: D

    Solution :

    \[_{72}{{A}^{180}}\xrightarrow{-\alpha }{{\,}_{70}}A_{1}^{176}\xrightarrow{-\beta }{{\,}_{71}}A_{2}^{176}\xrightarrow{-\alpha }\]                                                     \[_{69}A_{2}^{172}{{\xrightarrow{\gamma }}_{69}}A_{4}^{172}\]


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