A) \[6.4\times {{10}^{-3}}\]
B) \[3.2\times {{10}^{-4}}\]
C) \[9.6\times {{10}^{-3}}\]
D) \[1.28\times {{10}^{-2}}\]
Correct Answer: D
Solution :
Rate constant almost gets doubled by the increase of \[{{10}^{o}}C\] in temperature. Hence, the rate constant at 310 K will be \[=3.2\times {{10}^{-3}}\times {{(2)}^{2}}\] (\[\because \] increase in temperature = 20 K) \[=1.28\times {{10}^{-2}}\,{{J}^{-1}}\]
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