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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2004

  • question_answer
    If a tangent to the curve \[y=6x-{{x}^{2}}\] is parallel to the line \[4x-2y-1=0\], then the point of tangency on the curve is :

    A)  (2, 8)                    

    B)  (8, 2)

    C)  (6, 1)                    

    D)  (4, 2)

    Correct Answer: A

    Solution :

    Since tangent is parallel to \[y=2x-\frac{1}{2}\] \[\therefore \] equation of tangent is \[y=2x+\lambda \] The point of tangency will be the point of intersections of tangent and curve but in the given options only option  satisfied the equation of curve, then (2, 8) will be the point of tangency.


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