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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2004

  • question_answer
    In a triangle ABC if \[b=2,B={{30}^{o}}\] then the area of the circumcircle of triangle ABC in square units is :

    A)  \[\pi \]                                

    B)  \[2\,\pi \]

    C)  \[4\,\pi \]                                          

    D)  \[6\,\pi \]

    Correct Answer: C

    Solution :

    Here, \[b=2,B={{30}^{o}}\] \[\therefore \]  \[R=\frac{b}{2\sin B}=\frac{2}{2\sin {{30}^{o}}}=\frac{2}{1}\]                 \[R=2\] Area of circumcircle \[=\pi \,{{R}^{2}}\]                 \[=\pi \times {{(2)}^{2}}\] \[=1=4\pi \] isq. Units


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