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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2004

  • question_answer
    The maximum current that can be measured by a galvanometer of resistance \[40\,\,\Omega \], is 10 mA. It is converted into a voltmeter that can read upto 50 V. The resistance to be connected in series with the galvanometer (in ohms) is:

    A)  2010                                     

    B)  4050

    C)  5040                                     

    D)  4960

    Correct Answer: D

    Solution :

    To convert a galvanometer into voltmeter, the necessary value of resistance to be connected in series with the galvanometer is                 \[R=\frac{V}{{{I}_{g}}}-G\]                 \[=\frac{50}{10\times {{10}^{-3}}}-40\]                 \[=5000-40\]                 \[=4960\,\Omega \]       


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