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  3. CET Karnataka Engineering

CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    Molarity of \[0.2\,N\,{{H}_{2}}S{{O}_{4}}\] is :

    A)  0.2                                        

    B)  0.4

    C)  0.6                                        

    D)  0.1

    Correct Answer: D

    Solution :

    Normality of acid = molarity x basicity Molarity \[=\frac{N}{Basicity}\]                 \[=\frac{0.2}{2}=0.1\,M\]


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