CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    If the potential difference across the internal resistance \[{{r}_{1}}\] is equal to the emf E of die battery, then:

    A)  \[R={{r}_{1}}+{{r}_{2}}\]                             

    B)  \[R=\frac{{{r}_{1}}}{{{r}_{2}}}\]

    C)  \[R={{r}_{1}}-{{r}_{2}}\]                              

    D)  \[R=\frac{{{r}_{2}}}{{{r}_{1}}}\]

    Correct Answer: C

    Solution :

    The total emf \[=E+E=2\,E\] Total resistance \[=R+{{r}_{1}}+{{r}_{2}}\] \[\therefore \] Current flowing through the circuit                 \[i=\frac{2E}{R+{{r}_{1}}+{{r}_{2}}}\] According to question \[E=i{{r}_{1}}\Rightarrow \,i=\frac{E}{{{r}_{1}}}\] \[\therefore \]  \[\frac{E}{{{r}_{1}}}=\frac{2F}{R+{{r}_{1}}+{{r}_{2}}}\]                 \[R={{r}_{1}}-{{r}_{2}}\]


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