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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    The value of\[\cos \left( {{270}^{o}}+\theta  \right)\cos \left( {{90}^{o}}-\theta  \right)-\sin \left( {{270}^{o}}-\theta  \right)\cos \theta \]is :

    A)  0                                            

    B)  - 1

    C)  1/2                                       

    D)  1

    Correct Answer: D

    Solution :

    \[\cos \,({{270}^{o}}+\theta )\,\cos \,({{90}^{o}}-\theta )\]                                 \[-\sin \,({{270}^{o}}-\theta )\,\cos \theta \] \[=\sin \,\theta \,.\,\,\sin \theta +\cos \theta \,.\,\cos \theta \] \[={{\sin }^{2}}\theta +{{\cos }^{2}}\theta =1\]


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