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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    The sum to infinity of the progression\[9-3+\frac{1}{3}+.........\] is :

    A)  9                                            

    B)  9/2

    C)  27/4                                     

    D)  15/2

    Correct Answer: C

    Solution :

    Given series is   \[9-3+1-\frac{1}{3}+\,.......\,\,\infty \] This is an infinite G.P. series, here      \[a=9,\,\,\,r=-\frac{1}{3}\]                 \[{{S}_{\infty }}=\frac{a}{1-r}=\frac{9}{1-\left( -\frac{1}{3} \right)}\]                 \[=\frac{9}{\frac{4}{3}}=\frac{27}{4}\]


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