A) 200
B) 100
C) 10
D) 50
Correct Answer: B
Solution :
Let the resistance of voltmeter is \[G\,\,\Omega \]. \[\therefore \] Total resistance of the circuit \[R=\left( \frac{G\times 100}{G+100}+50 \right)\,\Omega \] Total current \[i=\frac{V}{R}\] \[=\frac{10}{\left( \frac{G\times 100}{G\times 100}+50 \right)}\] Voltage across 100 Q resistance \[=i\,\left( \frac{G\times 100}{G+100} \right)=\frac{10}{\left( \frac{G\times 100}{G\times 100}+50 \right)}\times \left( \frac{G\times 100}{G+100} \right)\] Reading of voltmeter = 5 volts \[\therefore \] Voltage across \[100\,\,\Omega =5\] volts \[\therefore \] \[=\frac{10}{\left( \frac{G\times 100}{G+100}+50 \right)}\times \left( \frac{G\times 100}{G+100} \right)\] On solving \[G=100\,\,\Omega \]
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