A) -1
B) 1
C) 0
D) \[\frac{1}{2}\]
Correct Answer: B
Solution :
\[\int_{\pi /4}^{\pi /2}{\cos e{{c}^{2}}x\,dx=[-\cot \,x]_{\pi /4}^{\pi /2}}\left( -\cot \frac{\pi }{2}+\cot \frac{\pi }{4} \right)\]\[=-[0-(1)]=1\]
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