2. Solved Papers
  3. CET Karnataka Engineering

CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    For the reaction\[{{N}_{2(g)}}+{{O}_{2(g)}}2N{{O}_{(g)}}\], the value of \[{{K}_{c}}\] at \[{{800}^{o}}C\] is 0.1. When the equilibrium concentration of both die reactants is 0.5 mol, what is the value of \[{{K}_{p}}\] at the same temperature?

    A)  0.5                                        

    B)  0.1

    C)  0.01                                      

    D)  0.025

    Correct Answer: B

    Solution :

    \[{{N}_{2}}(g)+{{O}_{2}}(g)2NO\,\,(g)\] \[{{K}_{c}}=0.1,\,{{K}_{p}}={{K}_{c}}\,{{(RT)}^{\Delta n}}\] \[\Delta n=\] Number of gaseous product                 - Number of gaseous reactants                 \[\Delta n=2-2=0\]                 \[\Delta n=0\] \[\therefore \]  \[{{K}_{p}}={{K}_{c}}=0.1\]


You need to login to perform this action.
You will be redirected in 3 sec spinner