A) \[{{10}^{-4}}M\,AgN{{O}_{3}}\] and \[{{10}^{-7}}M\,HCl\]
B) \[{{10}^{-5}}M\,AgN{{O}_{3}}\] and \[{{10}^{-6}}M\,HCl\]
C) \[{{10}^{-5}}M\,AgN{{O}_{3}}\] and \[{{10}^{-4}}M\,HCl\]
D) \[{{10}^{-6}}M\,AgN{{O}_{3}}\] and \[{{10}^{-6}}M\,HCl\]
Correct Answer: C
Solution :
A precipitate of \[AgCl\] is formed when equal volumes of \[{{10}^{-5}}M\,AgN{{O}_{3}}\] and \[{{10}^{-5}}M\,HCl\] are mixed, because ionic product will be \[{{10}^{-9}}\] which is greater than \[{{K}_{sp}}({{10}^{-10}})\]. For the precipitation of an electrolyte, it is necessary that the ionic product must exceed its solubility product.
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