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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2006

  • question_answer
    For a reaction \[A+B\xrightarrow{{}}C+D\] if the concentration of A is doubled without alteming the concentration of B, the rate gets doubled. If the concentration of B is increased by nine times without alteming the concentration of A, the rate gets tripled. The order of the reaction is :

    A)  2                                            

    B)  1

    C)  3/2                                       

    D)  4/3

    Correct Answer: C

    Solution :

                    \[A+B\xrightarrow{{}}C+D\] Rate       \[(r)=k{{[A]}^{a}}{{[B]}^{b}}\]                                    ... (i)                 \[2r=k{{[2A]}^{a}}{{[B]}^{b}}\]                   ... (ii)                 \[3r=k{{[A]}^{a}}{{[9B]}^{b}}\]                   ... (iii) Dividing Eq. (ii) by Eq. (i) \[2={{2}^{a}}\]or \[a=1\] Dividing Eq. (iii) by Eq. (i) \[3={{9}^{b}}\]or \[3={{3}^{2b}}\]or \[2b=1\]or \[b=\frac{1}{2}\] So, order of reaction \[=1+\frac{1}{2}=\frac{3}{2}\]                                 \[\Delta {{T}_{b}}=i\,.\,{{K}_{b}}\,.\,M\]


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