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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2006

  • question_answer
    A cyclist starts from the centre 0 of a circular park of radius 1 km, reaches the edge P of the park, then cycles along the circumference and returns to the centre along O as shown in the figure. If the round trip takes 10 min, the net displacement and average speed of the cyclist (in meters and kilometre per hour) are:

    A)  \[0,1\]                                 

    B)  \[\frac{\pi +4}{2},0\]

    C)  \[21.4,\frac{\pi +4}{2}\]                               

    D)  \[0,21.4\]

    Correct Answer: D

    Solution :

    Since, the initial position of cyclist coincides with final position, so his net displacement I zero. Average speed \[=\frac{total\text{ }distance\text{ }travelled}{total\text{ }time\text{ }taken}\]                 \[=\frac{OP+PQ+QO}{10}km/\min \].                 \[=\frac{1+\frac{\pi }{2}\times 1+1}{10}km/\min \]                 \[=\frac{\pi +4}{20}\times 60\,km/\min \]                 \[=21.4\,km/h\]


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