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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    What is the equivalent weight of \[SnC{{l}_{2}}\] in the following reaction\[SnC{{l}_{2}}+C{{l}_{2}}\xrightarrow{{}}SnC{{l}_{4}}?\] 

    A)  95                                         

    B)  45

    C)  60                                         

    D)  30

    Correct Answer: A

    Solution :

    \[\underset{190}{\mathop{SnC{{l}_{2}}}}\,+\underset{71}{\mathop{C{{l}_{2}}}}\,\xrightarrow{{}}SnC{{l}_{4}}\] \[\frac{190}{{{E}_{1}}}=\frac{71}{35.5}\] \[{{E}_{1}}\,\,\,\,=\,\,\,\,95\]


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