2. Solved Papers
  3. CET Karnataka Engineering

CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    The remainder obtained when \[{{5}^{124}}\]is divided by \[124\] is

    A)  \[5\]                                    

    B)  \[0\]

    C)  \[2\]                                    

    D)  \[1\]

    Correct Answer: A

    Solution :

    We have,  \[{{5}^{124}}={{({{5}^{3}})}^{41}}.5\] Now,                     \[{{5}^{3}}=1(\bmod \,\,124)\] \[\therefore \]  \[{{({{5}^{3}})}^{41}}=1(\bmod \,124)\]                 \[{{({{5}^{3}})}^{41}}.5=1.5(\bmod \,124)\] \[\Rightarrow \]               \[{{5}^{124}}=5\,(\bmod \,124)\]


You need to login to perform this action.
You will be redirected in 3 sec spinner