A) 0.25 H
B) 0.4 H
C) 2.5 H
D) 4 H
Correct Answer: C
Solution :
Induced emf, \[e=\frac{-L\,dI}{dt}\] \[\therefore \] \[100=\frac{-L\,[0-4]}{0.1}\] \[\Rightarrow \] \[L=\frac{100\times 0.1}{4}\] = 2.5 H
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