CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    Two thin equiconvex lenses each of focal length 0.2 m are placed coaxially with their optic centres 0.5 m apart. Then the focal length of the combination is

    A)  -0.4 m                                 

    B)  0.4 m

    C)  - 0.1 m                                

    D)  0.1 m

    Correct Answer: A

    Solution :

    Equivalent focal length (F) of two lenses separated by distance d is given by                 \[\frac{1}{F}=\frac{1}{{{f}_{1}}}+\frac{1}{{{f}_{2}}}-\frac{d}{{{f}_{1}}{{f}_{2}}}\]                 \[=\frac{1}{0.2}+\frac{1}{0.2}-\frac{0.5}{(0.2)\,(0.2)}\]                 \[=5+5-0.5\times 5\times 5\]                 \[=10-12.5\]                 \[=-2.5\] \[\therefore \]  \[F=-\frac{1}{2.5}=-0.4\,\,m\]


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