A) 2 mC
B) \[2\times {{10}^{-7}}C\]
C) 2 nC
D) \[2\,\mu C\]
Correct Answer: D
Solution :
Coulomb force is given by \[F=\frac{1}{4\,\pi \,{{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] \[\therefore \] \[(10\times {{10}^{-3}})\times 10=\frac{(9\times {{10}^{9}})\times {{q}^{2}}}{{{(0.6)}^{2}}}\] \[[\because \,\,{{q}_{1}}={{q}_{2}}=q]\] or \[{{q}^{2}}=\frac{{{10}^{-1}}\times 0.36}{9\times {{10}^{9}}}\] \[=4\times {{10}^{-12}}\] \[\therefore \] \[q=2\times {{10}^{-6}}C=2\mu C\]
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