A) 9
B) 18
C) 3
D) 27
Correct Answer: D
Solution :
In series arrangement potential difference is the sum of the individual potential difference of each capacitor. ie, \[V={{V}_{1}}={{V}_{1}}+{{V}_{2}}+{{V}_{3}}\] \[\therefore \] \[600=x\times 200\] \[x=3\] So, there should be 3 capacitors in series to obtain the required potential difference. The equivalent capacitance of the 3 capacitors in series is \[\frac{1}{{{C}_{eq}}}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}\] \[{{C}_{eq}}=2\] Now, we require \[18\,\mu F\] capacitance, for this we need 9 such combinations in parallel. Hence, \[9\times 3=27\]
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