A) z is purely real
B) z is purely imaginary
C) z is any complex number
D) real part of z is the same as its imaginary part
Correct Answer: B
Solution :
Let \[z=x+iy\] Given, \[z=-\bar{z}\] \[\therefore \] \[x+iy=-(\overline{x+iy})\] \[\Rightarrow \] \[x+iy=-(x-iy)\] \[\Rightarrow \] \[2x=0\] \[\Rightarrow \] \[x=0\] Hence, z is a purely imaginary.
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