CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2008

  • question_answer
    A current of 5 A is flowing at 220 V in the primary coil of a transformer. If the voltage produced in the secondary coil is 2200 V and 50% of power is lost, then the current secondary will be

    A)  2.5 A                                    

    B)  5 A

    C)  0.25 A                                  

    D)  0.5 A

    Correct Answer: C

    Solution :

    \[{{V}_{P}}=220\,V,\,\,{{V}_{s}}=2200\,V,\,\,{{I}_{P}}=5\,A,\,\,{{I}_{s}}=?\] Power loss = 50% Efficiency of transformer (n) is defined as the ratio of output power and input power ie,           \[\eta %=\frac{{{P}_{out}}}{{{P}_{in}}}\times 100=\frac{{{V}_{s}}{{I}_{s}}}{{{V}_{p}}{{I}_{p}}}\times 100\]                 \[50=\frac{2200\times {{I}_{s}}}{220\times 5}\times 100\]                 \[{{I}_{s}}=0.25\,A\]


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