CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2008

  • question_answer
    If \[{{\mu }_{0}}\] is permeability of free space and \[{{\varepsilon }_{0}}\] is permittivity of free space, the speed of light in vacuum is given by

    A)  \[\sqrt{{{\mu }_{0}}{{\varepsilon }_{0}}}\]                          

    B)  \[\sqrt{\frac{{{\mu }_{0}}}{{{\varepsilon }_{0}}}}\]

    C)  \[\sqrt{\frac{1}{{{\varepsilon }_{0}}{{\mu }_{0}}}}\]                       

    D)  \[\sqrt{\frac{{{\varepsilon }_{0}}}{{{\mu }_{0}}}}\]

    Correct Answer: C

    Solution :

    The speed of light in vacuum is given by\[\sqrt{\frac{1}{{{\mu }_{0}}\,{{\varepsilon }_{0}}}}\]. where \[{{\mu }_{0}}\] is permeability and \[{{\varepsilon }_{0}}\] is permittivity of free space.


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