A) \[1:4\]
B) \[1:2\]
C) \[1:3\]
D) \[1:6\]
Correct Answer: A
Solution :
Let initial activity of both substances are same. \[\therefore \] \[R={{R}_{0}}{{\left( \frac{1}{2} \right)}^{n}}={{R}_{0}}{{\left( \frac{1}{2} \right)}^{t/{{t}_{1}}/2}}\] \[\Rightarrow \] \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{\left( \frac{1}{2} \right)}^{4/1}}}{{{\left( \frac{1}{2} \right)}^{4/2}}}=\frac{{{\left( \frac{1}{2} \right)}^{4}}}{{{\left( \frac{1}{2} \right)}^{2}}}={{\left( \frac{1}{2} \right)}^{2}}\] \[\Rightarrow \] \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{1}{4}\]
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