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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2009

  • question_answer
    The rms velocity of molecules of a gas of density \[4\,kg\,{{m}^{-3}}\] and pressure \[1.2\times {{10}^{5}}N{{m}^{-2}}\] is

    A)  \[300\,\,m{{s}^{-1}}\]                  

    B)  \[900\,\,m{{s}^{-1}}\]

    C)  \[120\,\,m{{s}^{-1}}\]                  

    D)  \[600\,\,m{{s}^{-1}}\]

    Correct Answer: A

    Solution :

    \[{{v}_{rms}}=\sqrt{\frac{3p}{d}}\]                 \[=\sqrt{\frac{3\times 1.2\times {{10}^{5}}}{4}}=300\,\,m{{s}^{-1}}\]


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