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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2009

  • question_answer
    5 moles of \[S{{O}_{2}}\] and 5 moles of \[{{O}_{2}}\] are allowed to react. At equilibrium, it was found that 60% of \[S{{O}_{2}}\] is used up. If the partial pressure of the equilibrium mixture is one atmosphere, the partial pressure of \[{{O}_{2}}\] is

    A)  0.82 atm             

    B)  0.52 atm

    C)  0.21 atm             

    D)  0.41 atm 

    Correct Answer: D

    Solution :

                    \[2S{{O}_{2}}(g)+{{O}_{2}}(g)2S{{O}_{3}}(g)\]
    Initial 5 5 0
    At equilibrium (5 - 3 ) (5 - 1 .5) 3
    = 2 = 3.5
    \[\therefore \]  \[p{{O}_{2}}=\frac{3.5\times 1}{8.5}=0.41\,\,atm\]


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