A) \[1\]
B) \[\frac{1}{2}\]
C) \[\frac{3}{2}\]
D) \[0\]
Correct Answer: D
Solution :
Given., \[f(x)=\frac{g(x)+g(-x)}{2}+\frac{2}{{{[h(x)+h(-x)]}^{-1}}}\] \[\Rightarrow \] \[f(x)=\frac{g(x)+g(-x)}{2}+2[h(x)+h(-x)]\] On differentiating w.r.t.x, we get \[f'(x)=\frac{g'(x)-g'(-x)}{2}+2[h'(x)-h'(-x)]\] \[\therefore \] \[f'(0)=\frac{g'(0)-g'(0)}{2}+2[h'(0)-h'(0)]\] \[=0\]You need to login to perform this action.
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