A) \[2\]
B) \[3\]
C) \[5\]
D) \[0\]
Correct Answer: B
Solution :
\[{{(2{{+}_{6}}{{3}^{-1}}{{+}_{6}}4)}^{-1}}={{(2{{+}_{6}}3{{+}_{6}}4)}^{-1}}\,\,\,(\because \,\,{{3}^{-1}}=3)\] \[={{(5{{+}_{6}}4)}^{-1}}={{(3)}^{-1}}\] \[=3\]You need to login to perform this action.
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