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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2009

  • question_answer
    A stone is thrown vertically upwards from the top of a tower \[64\text{ }m\]high according to the law \[s=48t-16{{t}^{2}}.\]The greatest height attained by the stone above ground is

    A)  \[36\,m\]                                           

    B)  \[32\,m\]

    C)  \[100\,\,m\]                                     

    D)  \[64\,\,m\]

    Correct Answer: C

    Solution :

    Given,    \[s=48t-16{{t}^{2}}\] \[\Rightarrow \]               \[\frac{ds}{dt}=48-32t\] At the greatest height, \[v=\frac{dx}{dt}=0\] \[\Rightarrow \]               \[48-32t=0\] \[\Rightarrow \]               \[t=\frac{3}{2}\] \[\therefore \]  \[s=48\times \frac{3}{2}-16{{\left( \frac{3}{2} \right)}^{2}}\]                 \[=36m\] \[\therefore \] Total height \[=64+36=100m\]


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