A) \[20\text{ }log\text{ }2\text{ }yr\]
B) \[10\text{ }log\text{ }2\text{ y}r\]
C) \[5\text{ }log\text{ }2\text{ }yr\]
D) \[2\text{ }log\text{ }10\text{ }yr\]
E) None of these
Correct Answer: E
Solution :
Given, \[r=10%\] Let population is p. According to the question \[2P=P{{\left( 1+\frac{10}{100} \right)}^{n}}\] \[\Rightarrow \] \[2={{\left( 1+\frac{1}{10} \right)}^{n}}\] \[\Rightarrow \] \[\log 2=n(\log \,11-\log \,10)\] \[\Rightarrow \] \[n=\frac{\log 2}{1.0414-1}=\frac{\log 2}{0.0414}\] \[=24.15\log 2\] Hence, none of the given option is correct.
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