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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2009

  • question_answer
    If \[\vec{a}.\vec{b}=-|\vec{a}||\vec{b}|,\]then the angle between \[\vec{a}\] and \[\vec{b}\]  is

    A)  \[{{45}^{o}}\]                                   

    B)  \[{{180}^{o}}\]

    C)  \[{{90}^{o}}\]                                   

    D)  \[{{60}^{o}}\]

    Correct Answer: B

    Solution :

    Given,   \[\vec{a}.\vec{b}=-|\vec{a}||\vec{b}|\] \[\Rightarrow \]               \[|\vec{a}||\vec{b}|\cos \theta =-|\vec{a}||\vec{b}|\] \[\Rightarrow \]               \[\cos \theta =-1\] \[\Rightarrow \]               \[\theta ={{180}^{o}}\]


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