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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2009

  • question_answer
    In the group \[G\{0,1,2,3,4,5\}\] under addition modulo \[6,{{(2{{+}_{6}}{{3}^{-1}}{{+}_{6}}4)}^{-1}}\] is equal to

    A)  \[2\]                                    

    B)  \[3\]

    C)  \[5\]                                    

    D)  \[0\]

    Correct Answer: B

    Solution :

    \[{{(2{{+}_{6}}{{3}^{-1}}{{+}_{6}}4)}^{-1}}={{(2{{+}_{6}}3{{+}_{6}}4)}^{-1}}\,\,\,(\because \,\,{{3}^{-1}}=3)\] \[={{(5{{+}_{6}}4)}^{-1}}={{(3)}^{-1}}\] \[=3\]


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