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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2009

  • question_answer
    For the reaction \[{{H}_{2}}O(l){{H}_{2}}O(g)\] at 373 K and 1 atm pressure

    A)  \[\Delta H=0\]                 

    B)  \[\Delta E=0\]

    C)  \[\Delta H=T\Delta S\]                 

    D)  \[\Delta H=\Delta E\]

    Correct Answer: C

    Solution :

    \[\Delta G=\Delta H-T\,.\,\Delta S\] For the reaction,                                 \[{{H}_{2}}O(l){{H}_{2}}O(g)\]                 \[\Delta G=0\]                   (at equilibrium) \[\therefore \]  \[\Delta H=T\,.\,\Delta S\]


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