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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2010

  • question_answer
    The dimensions of resistance are same as those of..... .where h is the Planck's constant, e is the charge.

    A) \[\frac{{{h}^{2}}}{{{e}^{2}}}\]                                    

    B) \[\frac{{{h}^{2}}}{e}\]

    C) \[\frac{h}{{{e}^{2}}}\]                                   

    D) \[\frac{h}{e}\]

    Correct Answer: C

    Solution :

    Resistance, \[R=\frac{V}{i}=\frac{W}{qi}=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[{{A}^{2}}T]}\]                 \[R=[M{{L}^{2}}{{T}^{-3}}{{A}^{-2}}]\] For         \[\left[ \frac{h}{{{e}^{2}}} \right]=\frac{[M{{L}^{2}}{{T}^{-1}}]}{{{[AT]}^{2}}}=[M{{L}^{2}}{{T}^{-3}}{{A}^{-2}}]\]


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