A) 100%
B) 125%
C) 225%
D) 25%
Correct Answer: B
Solution :
Kinetic energy of the body, \[K=\frac{{{p}^{2}}}{2m}\] Since, the mass remains constant \[\therefore \] \[K\propto {{p}^{2}}\] \[\frac{{{K}_{2}}}{{{K}_{1}}}=\frac{p_{2}^{2}}{p_{1}^{2}}={{\left[ \frac{150}{100} \right]}^{2}}=\frac{9}{4}\] \[100\left[ \frac{{{K}_{2}}}{{{K}_{1}}}-1 \right]=\left( \frac{9}{4}-1 \right)\times 100=125%\]
You need to login to perform this action.
You will be redirected in
3 sec
