CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2010

  • question_answer
    A point object O is placed in front of a glass rod having spherical end of radius of curvature 30 cm. The image would be formed at

    A) 30 cm left           

    B) infinity

    C) 1 cm to the right              

    D) 18 cm to the left

    Correct Answer: A

    Solution :

    By using formula, \[\frac{{{\mu }_{2}}}{v}-\frac{{{\mu }_{1}}}{u}=\frac{{{\mu }_{2}}-{{\mu }_{1}}}{R}\] \[\Rightarrow \]               \[\frac{1.5}{v}-\frac{1}{(-15)}=\frac{(1.5-1)}{+30}\Rightarrow v=-30\,\,cm\] Negative sign shows that, image is obtained on the same side of object ie, towards left.


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