A) an aldehyde
B) a primary alcohol
C) a secondary alcohol
D) acetone
Correct Answer: B
Solution :
Because the difference in mass between\[-C{{H}_{2}}OH\] group and \[-COOH\] group is 14, thus the compound which undergoes oxidation is a primary alcohol. (\[-C{{H}_{2}}OH\] is the functional group of primary alcohols.) \[\underset{\begin{smallmatrix} (R+31) \\ primary\text{ }alcohol \end{smallmatrix}}{\mathop{RC{{H}_{2}}OH}}\,\xrightarrow{[O]}\underset{\begin{smallmatrix} (R+45) \\ acid \end{smallmatrix}}{\mathop{RCOOH}}\,\]
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