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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2011

  • question_answer
    Eight equal drops of water are falling through air with a steady velocity of \[10\text{ }cm\text{ }{{s}^{-1}}\]. If the drops combine to form a single drop big in size, then the terminal velocity of this big drop is

    A)  \[40\text{ }cm{{s}^{-1}}\]           

    B)  \[10\text{ }cm{{s}^{-1}}\]

    C)  \[30\text{ }cm{{s}^{-1}}\]           

    D)  \[80\text{ }cm{{s}^{-1}}\]

    Correct Answer: A

    Solution :

    Here,                 \[v\propto {{r}^{2}}\] \[\therefore \]  \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{r_{1}^{2}}{{{8}^{2/3}}.\,\,{{r}^{2}}}\]                 \[\frac{10}{{{v}_{2}}}=\frac{1}{4}\]                 \[{{v}_{2}}=40\,cm/s\]


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