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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2011

  • question_answer
    The sum of the reciprocals of focal distances of a focal PQ of \[{{y}^{2}}=4ax\]is

    A) \[\frac{1}{a}\]                                   

    B)  a

    C)  \[2a\]                                  

    D) \[\frac{1}{2a}\]

    Correct Answer: A

    Solution :

    Equation of parabola \[{{y}^{2}}=4ax\] Total length of focal chord = 4a and half length of focal chord = 2a Now, sum of the reciprocals of focal distances \[=\frac{1}{2a}+\frac{1}{2a}=\frac{2}{2a}=\frac{1}{a}\]


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